.com.unity Forums
  The Official e-Store of Shrapnel Games

This Month's Specials

BCT Commander- Save $6.00
World Supremacy- Save $10.00

   







Go Back   .com.unity Forums > Shrapnel Community > Space Empires: IV & V

 
 
Thread Tools Display Modes
Prev Previous Post   Next Post Next
  #34  
Old June 9th, 2003, 11:08 PM
Jack Simth's Avatar

Jack Simth Jack Simth is offline
Major General
 
Join Date: Oct 2002
Posts: 2,174
Thanks: 0
Thanked 0 Times in 0 Posts
Jack Simth is on a distinguished road
Default Re: # of members ?

Quote:
Originally posted by Suicide Junkie:
Star masses can also be found by looking at colour, age, size, etc.
Getting the mass from the color, age, size, etc. implicitly uses G, as the plasma physics that produce such results include gravitational effects from the mass of the star. Again, G is used to calculate G, and as such is circular logic and is not reliable. Mind you, G is probably constant throughout the universe - but there isn't any good way to be certain of that until we get out there and measure things up close. Until then, G is constant makes for a good working theory, but it can't be proven.
Quote:
Originally posted by Suicide Junkie:

And having a third body in the system to observe helps a lot.

G can be calculated from the masses, distance between, and the observed acceleration.
For that, the masses have to be known. Getting the masses uses G, although sometimes it is implicit rather than explicit. Again, G is used to obtain G, which is circular reasoning; not reliable. Mind you, G is probably constant throughout the universe - but there isn't any good way to be certain of that until we get out there and measure things up close.

Without knowing both the masses and G, some simple numerical manipulation on the gravitational formulas can tell you that the distance and acceleration alone won't help:

F = G(M*m)/(d^2)
F' = G'(M'*m')/(d'^2)
A = F/m = (G*M)/(d^2)
A' = F'/m' = (G'*M')/(d'^2)
If A = A' and d = d', then
(G'*M')/(d^2) = (G*M)/(d^2)
-> (G'*M') = (G*M)

Example: Suppose G' = 2G:
-> 2G*M' = G*M -> 2M' = M -> M' = M/2

Then M' = M/2 results in the same acceleration for the same distance. The number of bodies won't make a difference for this aspect of things.
__________________
Of course, by the time I finish this post, it will already be obsolete. C'est la vie.
Reply With Quote
 

Bookmarks

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is On

Forum Jump


All times are GMT -4. The time now is 03:15 PM.


Powered by vBulletin® Version 3.8.1
Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
Copyright ©1999 - 2025, Shrapnel Games, Inc. - All Rights Reserved.